Question

In the adjoining figure A is the centre of the circle
and AM = 9cm . Line NM is tangent at M
and MN = 12cm . Find AN.
Solution : Line NM is tangent at M, AMN = _____ ( tangent theorem)

In AMN , AN2 = AM2 + NM2

(by pythagoras theorem)

AN2 = ___ + 122
= _____
AN = ____

Answer 1

Answer:

15 cm

Step-by-step explanation:

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Line LM is tangent at M

so angle AMN = 90 degree (tangnet theorem)

$AN^{2}= AM^{2}+ NM^{2}$

$AN^{2}= 81 +144 = 225$

AN = 15 cm

Answer 2

Answer:

By Pythagoras theorem

AN (square) = AM (square) + MN (square)

AN(square) = 9 ( square) + 12 ( square)

AN (square) = 81 + 144

AN (square) = 225

AN = 15