in the adjoining figure AB=AC and AD is bisector. The rule by which ∆ABD = ∆ACD
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in ∆ABD and ∆ACD
AB= AC
it means ABC is isoceles triangle
by property of isoceles triangle
/ABD=/ACD
and AD bisects the BC so
BD= DC
by SAS congruency rule
∆ABD = ∆ACD
hence proved
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