In the adjoining figure AB=AC and BD=DC prove that angle BAD=angleCAD
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Answer:
Given:AB=AC
BD=CD
To prove that: ADB congruent to ADC
We have,
AB=AC(given)
BD=CD(given)
AD(common side)
Therefore, ADB ~ ADC (by SSS)
Also angle ADB =angle ADC (by c.p.c.t.)
But angleADB + angleADC = 180° (linear pair)
Implies that 2×angleADC = 180°
Implies that angleADC= 180°/2 = 90° = angle ADB
Hence, angleADC = angle ADB (Proved)
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