Question

in the adjoining figure AB= AC and D is the midpoint of BC . use SSS rule of congruency to show that
i) triangle ABD=~triangle ACD
ii) AD is bisector of angle A
iii) AD is perpendicular to BC​

Answer 1

Step-by-step explanation:

i) IN TRIANGLE ABD AND ADC

AB = AC (GIVEN)

AD = AD (COMMON SIDE)

BD = BC ( D IS THE MIDPOINT OF BC )

BY SSS AXIOM OF CONGRUENCY  ABD=~triangle ACD

ii) BY CONVERSE OF ANGLE BISECTOR THEOREM WHICH SAYS THAT " if a point D on the side BC of triangle ABC divides BC in the same ratio as the sides AB and AC, then AD is the angle bisector of angle ∠ A"

HENCE PROVED

PLZ FOLLOW ME AND MARK AS BRAINLIEST

Answer 2

In the adjoining figure AB= AC and D is the midpoint of BC . use SSS rule of congruency to show that

i) triangle ABD=~triangle ACD

ii) AD is bisector of angle A

iii) AD is perpendicular to BC

The answer is given above.

Hope it helps.