In the adjoining figure, AB = AC, D is a point in the
interior of AABC such that ZDBC = ZDCB. Prove that
AD bisects ZBAC of AABC.
Hint. ZDBC = ZDCB = CD = BD.
AABD = AACD by SSS rule of congruency.
B
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yes SSS rule of congruency b
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