Question

In the adjoining figure, AB =
AC, P and Q are
points on BA and CA respectively such that
AP = AQ. Prove that
(1) APC = AQB
(ii) CP = BQ
(iii) ACP = ABQ.
​

Answer 1

Answer:

(1)APC=AQB

In triangle APC&AQB

angle QAB=angle PAC (Vertically opposite angles)

AB=AC (Given)

BC= BC (Common)

By SAS criterion; triangleAPC=~ABQ

NOT sure about the answer

Answer 2

Step-by-step explanation:

I) In ∆APC and ∆AQB

<PAC= <QAB. ( vertically opposite angles)

AB=AC. (given)

AP=AQ. ( given)

therefore,∆APC is congruent to ∆ AQB