Question

in the adjoining figure AB=AD & CB = CD. Prove that ∆ABC congruent to ∆ADC​

Answer 1

$\underline\mathfrak\blue{Given\::-}$

• AB = AD
• CB = CD

$\underline\mathfrak\green{To\:Prove\::-}$

• ∆ABC ≅ ∆ ADC

$\underline\mathfrak\red{Proof\::-}$

In ∆ ABC AND ADC

• AB = AD ( given )
• CB = CD ( given )
• AC = AC ( common side )

by SSS congruency property,

∆ABC ≅ ∆ ADC

$\underline\mathfrak\orange{Please\:mark\:me\:as\:brainliest\::-}$

Answer 2

Step-by-step explanation:

Given : BC = CD, AD = AB

TO PROVE THAT : ΔADC ≡ ΔABC

Now, In ΔABC & ΔADC

BC = CD [ Given ]

AD = AB [ Given ]

AC = CA [ Common Side ]

∴ΔABC ≡ ΔADC by S.S.S test

Hence proved