Question

In the adjoining figure, AB = AD and CB = CD. Prove that ∆ABC ≅ ∆ADC.
plss give full formula

Answer 1

Answer:

Given= AB=AD, CB=CD

To prove:-  ∆ABC ≅ ∆ADC

Proof:- In  ∆ABC and ∆ADC

AB=AD(given)

CB=CD(given)

AC=AC(common)

∆ABC ≅ ∆ADC(by sss congruency rule)

Answer 2

Answer:

By SSS congruence criterion

Step-by-step explanation:

In ∆ ADC and ∆ ABC

AB = AD (GIVEN)

CB = CD (GIVEN)

AC = AC (COMMON IN BOTH ∆)

SO,∆ ABC ≈ ∆ ADC(BY SSS CONGRUENCE CRITERION)

ALL CRITERION:

SSS - IF THREE SIDES OF ONE ∆ IS EQUAL TO THREE SIDES OF OTHER ∆

SAS - IF 2 SIDES AND THE INCLUDED ANGLE IS EQUAL TO 2 SIDES AND INCLUDE ANGLE OF OTHER.

ASA-IF TWO ANGLE AND INCLUDED SIDES ARE EQUAL TO TWO ANGLE AND INCLUDED SIDED

RHS- IN TWO RIGHT ANGLE TRIANGLES IF ONE SIDE , HYPOTENUS AND ,90° ANGLE IS EQUAL.THEN THE CONGRUENT

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