In the adjoining figure AB=AD and CB=CD, Prove that
ΔABC≅ΔADC
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Given, AB = AD and CB = CD
To prove, ΔABC ≅ ΔADC.
Proof, In ΔABC and ΔADC
AB = AD (given)
CB = CD (given)
AC = AC (common)
∴ ΔABC ≅ ΔADC. (By SSS congruence property)
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