In the adjoining figure.
AB=AD and CB=CD
Prove that ∆ABC =~ ∆ADC
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Answered by
39
hey mate here is your answer
in triangle abc and adc
ab=ad( given )
bc=cd(given )
ac=ac (common)
triangle abc is congurent to adc (sss)
in triangle abc and adc
ab=ad( given )
bc=cd(given )
ac=ac (common)
triangle abc is congurent to adc (sss)
anjal85:
thanks
Answered by
19
Answer:
Step-by-step explanation:
AD=AB
CD=CB
and we can see that AC=AC {common}
hence TRIANGLE ABC=~TRIANGLE ADC
mark me as brainliest if it helps you.........
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