Question

in the adjoining figure , AB &CD are two vertical poles of height 19m and 11m respectively . if the distance between their tops is 17m , find the distance between their feet with explanation​

Answer 1

Answer:

15m

Step-by-step explanation:

construct draw a line from c horizontally which divide AB at E

AB=AE+EB

EB=CD=11m

AE=19-11=8m

AC=17m

CE=?

so AC²=EC²+AE²

17²=8²+EC²

EC²=289-64

EC=√225

EC=15m

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Answer 2

Answer:

Distance between feet of poles = 15 m

Step-by-step explanation:

Given:

• Distance between the tops = 17 m
• Height of the two poles = 19 m and 11 m

To Find:

• Distance between their feet

Solution:

We know that,

AB = 19 m and CD = 11m

Also AC = 17 m

We have to find the distance between the feets = BD

Join the points E and  C

Now,

EB = CD = 11 m

We know that

AE = AB = EB

AE = AB - CD

AE = 19 - 11

AE = 8 m

Now consider Δ AEC

By Pythagoras theorem,

AC² = AE² + EC²

Substitute the data,

17² = 8² + EC²

EC² = 17² - 8²

EC² = 289 - 64

EC² = 225

EC = √225

EC = 15

But we know that

BD = EC = 15 m

Hence distance between the feet of the poles is 15 m.