In the adjoining figure, AB and CD are vertical poles of height 19m and 11m respectively. if the shortest distance between their tops is 17m, find how far apart they are?
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Answered by
5
Basically use pythagorus theorum
Distance between the tops = 17
take this as the hypotenuse
The perpendicular = 19-11 = 8
Pythagorus theorum is
hypotenuse square= perpendicular square +base square
Thus by solving
base will be 15
which is the answer
Distance between the tops = 17
take this as the hypotenuse
The perpendicular = 19-11 = 8
Pythagorus theorum is
hypotenuse square= perpendicular square +base square
Thus by solving
base will be 15
which is the answer
Answered by
2
Answer:
Step-by-step explanation:
15
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