Question

in the adjoining figure AB and CD bisect each other at O
AC=BD ?



AC||BD ?​

Answer 1

Answer:

in trinagle ACO AND DOB

OD=OC(Given)

AO=BO(Given)

angleBOD=angleAOC(Vertically opposite angles)

thus,

traingles are congruent(S.A.S property)

therefore,

AC=BD(corresponding parts of congruent triangles are congruent)

and angle oca= angle odb(cpctc)

therefore,

ac||bd

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Answer 2

Answer:

triangle AOCcongruents to triangle BOC by side angle side [SAS]therefore AC=BD by CPCT and also angle OCA=angleODB thereforeACparallelBD