Math, asked by pallabid400, 3 months ago

In the adjoining figure, AB = CD, CE - BF and
ZACE = DBF Prove that
(1) AACE ADBF
(i) AE = DF
Hint. AB - CD - AB + BC = CDBC
ACBD

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Answers

Answered by syedsamisrvtrycbse

0

Answer:

Sorry

Step-by-step explanation:

I don't know maths.

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