Question

In the adjoining figure, AB = CD, CE = BF and
ZACE = ZDBF. Prove that
(i) AACE = ADBF
(ii) AE = DF.
B
Hint. AB = CD = AB + BC = CD + BC
AC = BD.
​

Answer 1

Step-by-step explanation:

Given: In the given figure

AB=CD

CE=BF

∠ACE=∠DBF

To proof:

AE=DF

Proof: AB=CD

Adding BC to both sides

AB+BC=BC+CD

AC=BD

Now in △ACE and △DBF

AC=BD (Proved)

CS=BF (Given)

∠ACE=∠DBF (SAS axiom)