Question

In the adjoining figure AB || CD. Line EF is the transversal. <EMD = 78° DMP = 32°, LPQB= 20°. Find the value of x and y​

Answer 1

Answer:

solution

Step-by-step explanation:

It is given that AB∥CD and BC is transversal

from the figure we know that ∠BCD and ∠ABC are alternate interior angles

so we get

∠ABC=∠BCD

in order to find the value of x we can write it as

x

o

+∠ECD=70

o

....(i)

It is given that CD∥EF and CE is transversal

from the figure we know that ∠ECD and ∠CEF are consecutive interior angles

so we get

∠ECD+∠CEF=180

o

by substituting the values

∠ECD+130

o

=180

o

∠ECD=180

o

−130

o

∠ECD=50

o

Now by substituting ∠ECD in equation (i) we get

x

o

+∠ECD=70

o

x

o

+50

o

=70

o

x

o

=20

o

therfore the value of x is 20

o

solution