Question

In the adjoining figure AB II CD and AB II EF .The value of x is​

Answer 1

Answer:

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Step-by-step explanation:

In given figure AB∥ED and EF∥CD

∠DEF=90−∠GEF=90−20=70

0

Given that EF∥CD and line ED join these

∴∠DEF=∠EDC=70

0

Join BD

∠CBD=90−∠ABC=90−50=40

0

∠CDB=90−∠CDE=90−70=20

0

In ΔBCD,

∠CBD+∠CDB+∠BCD=180

40+20+x=180

⇒x=180−40−20=120

0

Answer 2

Answer:

In given figure AB∥ED and EF∥CD

∠DEF=90−∠GEF=90−20=70

0

Given that EF∥CD and line ED join these

∴∠DEF=∠EDC=70

0

Join BD

∠CBD=90−∠ABC=90−50=40

0

∠CDB=90−∠CDE=90−70=20

0

In ΔBCD,

∠CBD+∠CDB+∠BCD=180

40+20+x=180

⇒x=180−40−20=120

0