Question

in the adjoining figure ab is a diameter of the circle if <acd=35° find the value of x​

Answer 1

Answer:

x=55°

Step-by-step explanation:

Angle ACD = Angle ABD = 35° (Angles in the same segment of a circle are equal)

Angle ADB =90° (The Angle in a semicircle is a right angle)

In triangle ABD:-

Angle BAD=180 - (90+35)

=180 - 125

=55° =x

Answer 2

The value of x=55 degrees

Step-by-step explanation:

AB is a diameter of circle

Angle ADB=90 degrees

Because angle subtended at half circle=90 degrees

Angle ACD=35 degrees

Angle ACD=Angle ABD

Angle subtended in the same segment of a circle   are equal.

Angle ABD=35 degrees

In triangle ABD

$\angle ABD+\angle ADB+\angle BAD=180$

By using triangle angles sum property

Substitute the values then we get

$35+90+x=180$

$125+x=180$

$x=180-125$

$x=55$

The value of x=55 degrees

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