Question

in the adjoining figure AB is parallel to CD and BF is parallel to GE . find X​

Answer 1

Answer:

$\huge \fbox \red{answer}$

Given: In the given figure

AB=CD

CE=BF

∠ACE=∠DBF

To proof:

AE=DF

Proof: AB=CD

Adding BC to both sides

AB+BC=BC+CD

AC=BD

Now in △ACE and △DBF

AC=BD (Proved)

CS=BF (Given)

∠ACE=∠DBF (SAS axiom)