Question

in the adjoining figure, AB is parallel to CD. Line segments BD and AC are perpendicular lines. Find angles BAO and CDO​

Answer 1

Answer:

angle BAO = 55°

angle CDO = 35°

Step-by-step explanation:

Acc. to ques.

angle COD=angle AOB=90°(vertically opposite angle)

angle CDO = angle ABO=x°(alternate angle)

now,

In ∆AOB

angle BAO+angleAOB+angle ABO=180°(angle sum property)

(2x-15)°+90°+x° =180°

3x+75° = 180°

3x=180°-75°=105°

x = 105/3

x= 35°

so, angle BAO = 2x-15°=2×35°-15° =55°

angle CDO = x° = 35°

Hope this will help you :)