In the adjoining figure, AB || QP and QR || BC.
If ZABC = 60°, then find ZPQR.
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Answered by
9
Answer:
∠PQR = 120
Step-by-step explanation:
it is given that AB║PQ
Give that ∠ABC = 60
Since AB║PQ, then
∠ABC = ∠QPC ( corresponding angles )
Therefore, ∠QPC = 60
∠QPC + ∠PQR = 180 ( Co - Interior )
60 + ∠PQR = 180
Therefore ∠PQR = 180 - 60 = 120
Answered by
1
Answer :-
AB.ll QP
/_ ABP = /_QPC.....Corresponding angle theorem
60°=/_QPC
Now,
QR ll BC i.e. QR ll PC
/_ RQP + /_QPC = 180°....Interior angle theorem
/_ RQP + 60° = 180°
/_RQP = 180 - 60
/_RQP = 120°
Hope it helps you
Thanks for the question bro
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