Question

in the adjoining figure ABC equal to ACD and D is the midpoint of BC. prove that ADB congruent to ADC

Answer 1

<B = <C since AB = AC 
Triangle ABC is an isosceles triangle
Now D is mid point of BC
So BD = CD
In triangles ADB and ADC, 
AD is common
BD = CD
AB = AC 
So by SSS rule both triangles are congruent
 

Answer 2

Answer:

Step-by-step explanation:

Hello....

Hey mate..

ABC is equal to ABD

(Given)

To prove ABC ~= ADC

ABC ABD

AC = AC (common)

Angle C = angle C (90 degree median)

BC. = CD (midpoint)

Under SAS criteria

ABC ~= ACD

Thus proved

PLZZ mark as brainliest answer

Thank u