Question

In the adjoining Figure, ABC is a triangle in which AD is the bisector of angle A. If AD is perpendicular to BC, show that ABC is isosceles​

Answer 1

Answer:

In triangle ADB and triangle ADC

1.<BAD=<CAD (given )

2.<ADB=<ADC (each 90⁰)

3.AD=AD (common side)

Hence it is proved that triangle ADB and triangle ADC are congruent

Therefore sideAB=side AC (c.p.c.t)

Now in triangle ABC

AB=AC (proved)

So in a triangle when two sides are equal it is known as an isosceles triangle

So it is proved that triangle ABC is a triangle

Step-by-step explanation:

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