In the adjoining figure, ABC is a triangle in which AD is the bisector of <A.
If AD perpendicular BC, show that triangle ABC is isosceles.
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Answer:
In triangle ABD and ACD
Angle BAD = Angle CAD [ As AD is bisector]
AD = AD [Common side]
Angle ADB = Angle ADC = 90degree [AD is perpendiculatr to BC]
Therefore, triangle ABC is congruent to triangle ACD by SAS congruence rule.
Now, angle B = angle C by CPCT.
Hence, AB=AC as the angles opposite to them are equal.
Therefore, triangle ABC is an isosceles triangle.
Hope this will help.
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