Question

. In the adjoining figure, ∆ABC is an isosceles triangle in which AB = AC.
If BM and AC are perpendicular and CN and AB are perpendicular, prove that:
(i) ∆BMC = ∆CNB
(ii) BM = CN
​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Step-by-step explanation:

in ∆ABC

AB=AC

so, angle ABC=angle ACB

or, angle NBC= angle MCB.......(1)

Now, in right∆CNB and ∆BMC

angle NBC=MCB. (from...1)

angle CNB=angle BMC. (each=90°)

and BC=BC. (common)

therefore, ∆BMC=~∆CNB

and also BM=CN (by CPCT)