Question

In the adjoining figure, ABC is an isosceles triangle
with AB = AC = 7.5 cm and BC = 9 cm. If the height
AD from A to BC is 6 cm, find:
(i) the area of AABC
(ii) the height CE from C to AB.​

Answer 1

Answer:

i.area=1/2 ×base×height

=1/2×9×6

=27

ii . height=2×area/Base

=2×27/9

=54/9

=6 cm

Answer 2

hope this helps u...........