Question

In the adjoining figure ,ABC is an isosceles triangle with AB=AC=7.5cm and BC =9cm. If the height AD from A to BC is 6cm,find
1. the area of ∆ABC
2.the height CE from C to AB

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Area of ΔABC = 27 cm²

Height CE=7.2 cm

Step-by-step explanation:

Base BC=9 cm

Height AD=6 cm

Area of ΔABC = $\frac{1}{2}$×Base×Height

=$\frac{1}{2}$×9 cm×6 cm

=27 cm²

Now let CE be the height and AB be the base

Area of ΔABC = 27 cm²

$\frac{1}{2}$×Base×Height = 27 cm²

$\frac{1}{2}$×7.5 cm×CE=27 cm²

CE= 27 cm²×$\frac{2}{7.5 cm}$

CE=7.2 cm

You can refer the diagram....

I hope you understood it.....

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