In the adjoining figure ABC is an isosceles triangle with AB = 7.5 m AC = 7.5cm and BC = 9 CM . If the hight AD from A to BC is 6 find i) area of ABC ii) The hight CE from C to AB.
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- area=1/2(AD)(BC)=1/2(6)(9)=27m²
- area=1/2(AD)(BC)=1/2(CE)(AB)
=>(6)(9)=(CE)(7.5)
=>(6)(6)=(CE)(5)
=>CE=36/5=7.2m
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