In the adjoining figure,ABC is an isosceles yriangle in which AB=AC. If D and F be the midpoints of AC and AB respectively, prove that BE=CD
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∆BDC is congruent to ∆CEB
Hence BE=CD ,(by c.p.c.t)
Hence BE=CD ,(by c.p.c.t)
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Amit1111111111:
how please say in full forumla
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ABC is an isosceles triangle therefore AB=AC
AB/2=AC/2
BE=CD(E &D ARE Mps of AB&AC
hope it will b helpful
AB/2=AC/2
BE=CD(E &D ARE Mps of AB&AC
hope it will b helpful
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