Question

In the adjoining figure, ABC is right-angled at B and angle A =45°. If AC =3√2 cm, find i BC, ii AB.​

Answer 1

Answer:

Step-by-step explanation:

By Pythagoras theorem

a^2 + b^2 = c^2

a^2 + b^2 = (3√2)^2

a^2+b^2 = 18

possible squares to add is

3^2 and 3^2

BC= 3cm

AB= 3cm

Answer 2

BC/AC = sin 45°

BC/3√2 =1/√2

Or BC = 3

By Pythagoras theorem

(AB)2 = (AC)2 – (BC)2

= (3√2)2 – (3)2

= 18 – 9

= 9

AB = 3 cm