Question

In the adjoining figure, ABCD is a cyclic quadrilateral. If AB is a diameter, BC = CD and ABD = 40°, find the measure of DBC.​

Answer 1

Answer:

In the cy.QRL Angle ADB= d =90 degree

(angle of Semicircle)

Angle A = 50 degree. (180-l30)

Angle C = 130degree. ( I80-50)

2x =180-130=50

x = 25° = AngleDBC. ANSWER

In a cyclic QRL the sum of opposite

angles are supplementary