In the adjoining figure, ABCD is a cyclic
quadrilateral. The line PQ is the tangent to the
circle at A. If ZCAQ : CAP = 1:2, AB bisects
ZCAQ and AD bisects ZCAP, then find the
measures of the angles of the cyclic quadrilateral.
Also prove that BD is a diameter of the circle.
B
P
A
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AB and AD are the bisectors of ZCAQ and ZCAP respectively and angle CAQ+angleCAB = 180° (linear pair)
.. angle CAB =angle CAD = 90°
angle BAD = 90°
Hence, BD is at diameter of the circle.
(ii). angleCAQ: angleCAP = 1:2
Let angleCAQx and angleCAP = 2x
x+2x= 180°( linear pair)
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