Question

In the adjoining figure, ABCD is a parallelogram, ABM is a line segment and E is the mid-point of BC. prove that:(a)angle DCE is parallel to angle MBE (b)AB=BM (c)Am=2DC
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Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

(i) a. BE = CE  {E is mid-point}

   b. angle BEL = angle CED

   c. angle LBE = angle DCE

So, triangle LBE is congruent to triangle DCE [A.S.A]

AB=CD

CD=BL {congruent parts of a congruent triangle are congruent (c.p.c.t.c. short form)

So, AB=BL

AB=BL=CD

so AB+BL=2CD

Hope this helps :)