In the adjoining figure, ABCD is a parallelogram and AP, CQ are perpendiculars from the vertices A, C
respectively on the diagonal BD. Show that
(i) ∆APB ≅ ∆CQD
(ii) AP = CQ.
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in triangle apb and triangle cqd
AB=CD
angle p= angle q = 90 degree
angle CD = angle qba ( alternate angles)
therefore apb is congruent to cqd
ap =cq cpct
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