in the adjoining figure, abcd is a parallelogram and ax is parallel to cy prove that ax =cy and axcy is a parallelogram
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AX and CY are respectively the bisectors of opposite angles A and C of a parallelogram ABCD. Show that AX is parallel to CY /
Given:
ABCD is a Parallelogram
AX is the bisector of ∠A
CY is the bisector of ∠C
To Prove
AX ║ CY
Proof :
ABCD is a parallelogram
∠A = ∠C (Opp. angles of a parallelogram are equal)
∠A/2 = ∠C/2 (Halves of equals are equal)
∴ ∠1 = ∠2 (AX and CY bisects A and C)
We know that:
AB ║CD and CY is the transversal (Parallel lines of a parallelogram)
∴ ∠2 = ∠3
But ∠1 = ∠2 as well.
Therefore from the above statements, we can conclude that:
⇒ ∠1 = ∠3 [Thins equal to the same thing are equal to one another]
∴ AX ║ CY
(Corresponding angles 1 and 3 are equal, therefore the lines are parallel)
Hence proved.
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