- In the adjoining figure, ABCD is a parallelogram and <A = 120°. If the
bisectors of <A and <B meet at a point P, show that <APB is a right
angle.
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Measure of angle B = 180-120=60
A bisector divides the angle into 2 equal parts
So in triangle APB
A = 60
B = 30
P = 180-(60+30)
= 90
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