In the adjoining figure, ABCD is a parallelogram. E and
F are mid-points of the sides AB and CD respectively,
The straight lines AF and BF meet the straight lines ED
and EC in points G and H respectively. Prove that
(1) AHEB = AHCF
(a) GEHF is a parallelogram,
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Answered by
42
Step-by-step explanation:
(I)angle EHB=angle FHC( vertical opp angle ) angle HCF= angleHEB (alternate ) angle HFC = angleHBD( alternate) ∆HEB=∆ HCF HF=HB(cpct). (ii) in ∆ABF GE// FB( by mid pnt Theron) GE// FH. GE=FHso GEHF is //gm .
Answered by
5
Answer:
In the adjoining figure, ABCD is a parallelogram. E and
F are mid-points of the sides AB and CD respectively,
The straight lines AF and BF meet the straight lines ED
and EC in points G and H respectively.
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