Question

In the adjoining figure, ABCD is a parallelogram. E and
F are mid-points of the sides AB and CD respectively,
The straight lines AF and BF meet the straight lines ED
and EC in points G and H respectively. Prove that
(1) AHEB = AHCF
(a) GEHF is a parallelogram,​

Answer 1

Step-by-step explanation:

(I)angle EHB=angle FHC( vertical opp angle ) angle HCF= angleHEB (alternate ) angle HFC = angleHBD( alternate) ∆HEB=∆ HCF HF=HB(cpct). (ii) in ∆ABF GE// FB( by mid pnt Theron) GE// FH. GE=FHso GEHF is //gm .

Answer 2

Answer:

In the adjoining figure, ABCD is a parallelogram. E and

F are mid-points of the sides AB and CD respectively,

The straight lines AF and BF meet the straight lines ED

and EC in points G and H respectively.