Math, asked by adityasingh25apr2006, 7 months ago

In the adjoining figure, ABCD is a parallelogram. E and
F are mid-points of the sides AB and CD respectively
The straight lines AF and BF meet the straight lines ED
and EC in points G and H respectively. Prove that
(1) triangle HEB is congruent to triangle HCF
(1) GEHF is a parallelogram,​

Answers

Answered by akshara1020
1

Answer:

fd

Step-by-step explanation:

by the parallelogram

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