In the adjoining figure, ABCD is a parallelogram If ∠=85°and ∠=60°Then calculate, a)∠cdb b)∠adb
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Step-by-step explanation:
a) angle DCB = angle DAB = 85°
in ∆ DCB, 60° + 85° + angle CDB = 180° [ angle sum property ]
therefore angle CDB = 35°
b) angle ADB = angle DBC = 60° [ interior alternate angles as AD is parallel to BC and BD is transversal ]
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