Question

in the adjoining figure ABCD is a parallelogram in which angle A = to 60 degree if the bisector of angle A and Angle B made DC at P prove that angle APB equals to 90 degree ​

Answer 1

Answer:

ABCD is a parallelogram in which angle A = 60 degree, if the bisectors of angle A and angle B meet DC at P, prove that (i) angle APB = 90 degree (ii) AD = DP and PB = PC=BC (iii) DC = 2AD.

Explanation:

hope you like it

mark me brainliest