In the adjoining figure, ABCD is a parallelogram in which angle A = 72° . Calculate angle B , angle C and angle D
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We know that in a parallelogram opposite angles are equal So we get ∠ A = ∠ C = 72o
We that that in a parallelogram the sum of all the angles is 360o
It can be written as ∠ A + ∠ B + ∠ C + ∠ D = 360o
By substituting the values in the above equation 72o + ∠ B + 72o + ∠ D = 360o
We know that ∠ A = ∠ C and ∠ B = ∠ D
So we can write it as 2 ∠ B + 144o = 360o
On further calculation 2 ∠ B = 360o – 144o
By subtraction 2 ∠ B = 216o
By division ∠ B = 108o
Therefore, ∠ B = 108o, ∠ C = 72o and ∠ D = 108o
We that that in a parallelogram the sum of all the angles is 360o
It can be written as ∠ A + ∠ B + ∠ C + ∠ D = 360o
By substituting the values in the above equation 72o + ∠ B + 72o + ∠ D = 360o
We know that ∠ A = ∠ C and ∠ B = ∠ D
So we can write it as 2 ∠ B + 144o = 360o
On further calculation 2 ∠ B = 360o – 144o
By subtraction 2 ∠ B = 216o
By division ∠ B = 108o
Therefore, ∠ B = 108o, ∠ C = 72o and ∠ D = 108o
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sorry don't know
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