Question

In the adjoining figure, ABCD is a parallelogram in which angle DAB =80° and angle DBC = 60°.Calculate angle CDB and angle ADB​

Answer 1

Answer:

1. As 80 degree is opposite to C therefore angle C will be 80 degree as it is the property of parallelogram .
2. Sum of all the angle is 180 degree so 60 +80 + angle BDC =180
3. angle CDB =40 degree
4. Now as CDB is alternate to angle DBA therefore angle DBA =40 degree
5. 40 +80+angle ADB =180 (Sum of angle in a triangle)
6. angle ADB =60 deegre .............

• HENCE THE IS ABOVE........

Answer 2

∠CDB=40°  ∠ABD=60°.

Step-by-step explanation: