Question

In the adjoining figure, ABCD is a parallelogram in which AB 28 cm,
BC = 25 cm and diagonal AC = 30 cm. Find
the area of parallelogram ABCD
w the distance between AB and DC.
w the distance between CB and DA​

Answer 1

Answer:

Where is the figure. please give figure

Answer 2

Answer:

the answer is (i) 674, (ii) 24cm, (iii) 25.84

Step-by-step explanation:

Area of triangle = √s (s-a) (s-b) (s-c)

side = a + b +c / 2

       = 28 + 26 + 30 / 2

       = 84 / 2 = 42

Area of triangle = √42 (42 - 28) (42 - 26) (42 - 30)

                          = √42 * 14 * 16 * 12

                          = 336 sqcm

Area of parallelogram = 336*2 = 672 sqcm

(ii) Area = base * height

    h= 672 / 28 = 24 cm

(iii) Area = base * height

      h = 672 * 26 = 25.85