Question

In the adjoining figure ABCD is a parallelogram in which E is the mid point of DC and F is a point on AC such that CF=1/4 of AC . if EF is produced to meet BC in G prove that G is the mid point of BC

Answer 1

Answer:

We know that the diagonals of a parallelogram bisect each other. Therefore, Therefore, according to midpoint theorem in ∆CSD PQ || DS If PQ || DS, we can say that QR || SB In ∆ CSB, Q is midpoint of CS and QR ‖ SB. Applying converse of midpoint theorem , we conclude that R is the midpoint of CB. This completes the proof.