Question

In the adjoining figure, ABCD is a parallelogram in which ZA = 60°. If the bisectors of ZA and
ZB meet DC at P
15)
8
A
Prove that
i. ZAPB = 90°
ii. AD = DP and PB = PC = BC
iii. DC = 2AD.​

Answer 1

Answer:

Please provide the given figure for this question.