In the adjoining figure, ABCD is a quadrilateral with diagonal AC and DB. If
AB = DC and ∆BCD = ∆CBA, show that
(a) ∆BCD ≈ ∆ABC congurent
(b) BCD≈BAD
(C) BCA = CBD
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Answer:
(a) to prove ΔBCD≈ΔABC,
∠BCD = ∠CBA (GIVEN)
CB = CB (COMMON )
AB = DC (GIVEN)
=> ΔBCD ≈ ΔABC ( SAS congruence rule )
Rest of the questions I dont know
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