Question

In the adjoining figure. ABCD is a rectangle and diagonals
intersect at 0. If ZAOB = 118, find
(0) ZABO
(ii) LADO
(in ZOCB
plz ans it soon ​

Answer 1

Answer:

Step-by-step explanation:

Hello friend, As we know that diagnols of rectangle form isosceles triangles.

If angle AOB= 118°

Then let angle ABO and OAB =x

x+x+118°=180°

2x= 180°-118°

x= 62°/2= 31°

So ABO= OAB=31°

ABO= ODC=31°

ADO= 90°-31°= 59°

OAB=OCD=31°

OCB= 90°-31°= 59°

Hope it helps☺