Question

in the adjoining figure ABCD is a rectangle b m and n are perpendicular from B and D respectively on AC prove that BM=DN ​

Answer 1

hope this helps

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Answer 2

In a triangles BMC and DNABC = DA (Opposite sides)

∠BCM = ∠DAN (alternate angles)

∠DNA = ∠BMC = 90° [DN and BM are perpendicular to AC]

So by AAS Congruency criterion

ΔBMC ≅ ΔDNA

BM = DN (By CPCT)