Question

in the adjoining figure abcd is a rectangle diagonal intersected at o.if<aob=118 find
i <abo
ii <ado
iii <ocb
you can see figure in image ques no 8

Answer 1

Hello friend, As we know that diagnols of rectangle form isosceles triangles.
If angle AOB= 118°
Then let angle ABO and OAB =x
x+x+118°=180°
2x= 180°-118°
x= 62°/2= 31°
So ABO= OAB=31°
ABO= ODC=31°
ADO= 90°-31°= 59°
OAB=OCD=31°
OCB= 90°-31°= 59°
Hope it helps☺

Answer 2

Hope this help. Please mark as Brainlyst