Question

In the adjoining figure, ABCD is a rectangle.If ZCEB: ZECB = 3:2, find(i) ZCEB(ii) ZDCF​

Answer 1

Answer:

since ABCD is rectangle

ZB = 90°

in ∆ CEB

acc to Ques

ZCEB= 3X

ZECB= 2X

ZB+ZC+ZE=180°

90°+3x+2x=180°

5x=90°

X=18°

ZCEB= 54°

ZECB =36°

ZC =90°

ZECB+ZECD =90°

36°+ZECD=90°

ZECD=54°

ZDCF=180-54

ZDCF=126°